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JAMB - Physics (2021 - No. 35)

The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 180Hz?
4
3
2
1

Giải thích

f\(_{0}\) = 40H\(_{3}\)

1st overtone = 2f\(_{0}\) = 80H\(_{3}\)

2nd overtone = 3f\(_{0}\) = 120H\(_{3}\)

3rd overtone = 4f\(_{0}\) = 160H\(_{3}\)

4th overtone = 5f\(_{0}\) = 200H\(_{3}\)

\(\therefore\) Number of overtones between 40H\(_{3}\) and 180H\(_{3}\) = 3

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