JAMB - Physics (2018 - No. 83)
When a known standard resistor of 2.0 is connected to the 0.0cm end of a metre bridge, the balance point is found to be at 55.0cm
1.10Ω
1.64Ω
2.44Ω
27.50Ω
Giải thích
\(\frac{R_1}{R_2}\) = \(\frac{(100- L_1)}{( L_1)}\)
\(\frac{R_1}{2}\) = \(\frac{45}{55}\)
R\(_1\) = 2 × \(\frac{45}{55}\)
= 1.64Ω
this is because the known resistor is connected to 0.00cm end and balances at 55cm