JAMB - Physics (2002 - No. 36)
\(^{23}_{11}\)Na + X → \(^{20}_9\)F + \(^4_2\)He
What particle is X in the reaction above?
Alpha
Beta
Neurons
Gamma
Giải thích
The particle in the reaction is a neutron
\(^{23}_{11}\)Na + \(^1_0\)n → \(^{20}_9\)F + \(^4_2\)He