JAMB - Physics (1995 - No. 9) | ExamPlay

JAMB - Physics (1995 - No. 9)

The energy contained in a wire when it extended by 0.02m by a force 500 N is

5J

10J

10³J

10⁴

Giải thích

Energy = \(\frac{1}{2}\)Fe

= \(\frac{1}{2}\) x 500 x 0.02

E = 5J

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