JAMB - Physics (1995 - No. 5)
A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 x 103km, g = 10ms-2]
14 kms-1
13 kms-1
12 kms-1
11 kms-1
Giải thích
Velocity = \(\sqrt2gR\)
= 2 x 6400 x 100 x 10
= 11 km-1
= 2 x 6400 x 100 x 10
= 11 km-1