JAMB - Physics (1990 - No. 2)
A car moving with a speed of 90kmh\(^{-1}\) was brought uniformly to rest by the application of the brakes in 10s. How far did the car travel after the brakes were applied?
125m
150m
250m
15km
Giải thích
speed = \(\frac{90 \times 10^3}{3600}\) = 25ms\(^{-1}\)
Acceleration = \(\frac{\text{velocity change}}{\text{time}}\) = \(\frac{25}{10}\)
: Acceleration = 2.5
Using S = Ut + \(\frac{1}{2}\) at\(^2\)
S = \(\frac{1}{2}\) X 2.5 X 10\(^2\) = 125m