JAMB - Physics (1987 - No. 4)
An elevator of mass 4800kg is supported by a cable which can safely withstand a maximum tension of 60 000N. The maximum upward acceleration the elevator can have is
2.5ms-2
5.0ms-2
7.5ms-2
10.0ms-2
Giải thích
a = \(\frac{F}{m}\)
= \(\frac{60000 -(4800 \times10)}{4800}\)
= 2.5ms-2
= \(\frac{60000 -(4800 \times10)}{4800}\)
= 2.5ms-2