JAMB - Physics (1985 - No. 2)
A simple pendulum with a period of 2.0s has its length doubled. Its new period is
1.00s
1.41s
0.3s
2.83s
4.00s
Giải thích
Using \(\frac{T_1}{T_2}\) = \(\sqrt\frac{L_1}{L_2}\)
\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)
T2 = 2.83sec
\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)
T2 = 2.83sec