JAMB - Physics (1985 - No. 13)
The areas of the effort and load pistons of a hydraulic press are 0.5m2 and 5m2 respectively. If a force F1 of 100N is applied on the effort piston, the force F2 on the load is
10N
100N
500N
1000N
5000N
Giải thích
\(\frac{load}{area}\) = \(\frac{effort}{area}\)
\(\frac{load}{5}\) = \(\frac{100}{0.5}\)
load = 1000N
\(\frac{load}{5}\) = \(\frac{100}{0.5}\)
load = 1000N