JAMB - Physics (1984 - No. 22)
A particle moves in a circular orbit of radius 0.02m. If the speed of the particle is 0.88ms-1, calculate its frequency in cycles per second
2.0Hz
7.0Hz
8.8Hz
14.0Hz
17.6Hz
Giải thích
W = \(\frac{v}{r}\)
= \(\frac{0.88}{0.02}\) = 44 rad/s
2\(\pi\)F = W = 44
F = \(\frac{44}{2 \times 3.142}\)
= 7Hz
= \(\frac{0.88}{0.02}\) = 44 rad/s
2\(\pi\)F = W = 44
F = \(\frac{44}{2 \times 3.142}\)
= 7Hz