JAMB - Physics (1983 - No. 26)
The total length of a spring when a mass of 20g is hung from its end is 14cm, while its total length is 16cm when a mass of 30g is hung from the same end. Calculate the unstretched length of the spring assuming Hooke's law is obeyed.
9.33cm
10.00cm
10.66cm
12.00cm
15.00cm
Giải thích
Let unstretched length = L
e1 = 14 - L and e2 = 16 - L
Using, \(\frac{m_1}{e_1}\) = \(\frac{m_2}{e_2}\)
\(\frac{20}{14 - L}\) = \(\frac{30}{16 - L}\)
L = 10cm
e1 = 14 - L and e2 = 16 - L
Using, \(\frac{m_1}{e_1}\) = \(\frac{m_2}{e_2}\)
\(\frac{20}{14 - L}\) = \(\frac{30}{16 - L}\)
L = 10cm