JAMB - Mathematics (2012 - No. 6)
If log3x2 = -8, what is x?
\(\frac{1}{3}\)
\(\frac{1}{9}\)
\(\frac{1}{27}\)
\(\frac{1}{81}\)
Giải thích
log3x2 = -8
x2 = 3-8
x = \(3^{-8 \times \frac{1}{2}}\)
x = 3-4
x = \(\frac{1}{3^4}\)
x = \(\frac{1}{81}\)
x2 = 3-8
x = \(3^{-8 \times \frac{1}{2}}\)
x = 3-4
x = \(\frac{1}{3^4}\)
x = \(\frac{1}{81}\)