JAMB - Mathematics (2009 - No. 28)
Find the locus of a particle which moves in the first quadrant so that it is equidistant from the lines x = 0 and y = 0 (where k is a constant)?
x + y = 0
x - y = 0
x + y + k = 0
x - y - k = 0
Giải thích
Locus of a particle which moves in the first quadrant so that it is equidistant from the lines
X = 0 and Y = 0 are the x and y axes as the lines bisecting the angle between x and y axes.