JAMB - Mathematics (2006 - No. 43)
If \(T = 2\pi \sqrt{\frac{l}{g}}\), make g the subject of the formula
(4π l2) / T
(4π2l) / T2
(4π2l2) / T2
(2π√l) / T
Giải thích
\(T = 2\pi \sqrt{\frac{l}{g}}\)
\(\frac{T}{2\pi} = \sqrt{\frac{l}{g}}\)
\((\frac{T}{2\pi})^{2} = \frac{l}{g}\)
\(\therefore g = \frac{4 \pi^{2} l}{T^{2}}\)