JAMB - Mathematics (1998 - No. 2)
Evaluate [\(\frac{1}{0.03}\) \(\div\) \(\frac{1}{0.024}\)]-1 correct to 2 decimal places
3.76
1.25
0.94
0.75
Giải thích
[\(\frac{1}{0.03}\) + \(\frac{1}{0.024}\)]
= [\(\frac{1}{0.03 \times 0.024}\)]-1
= [\(\frac{0.024}{0.003}\)]-1
= \(\frac{0.03}{0.024}\)
= \(\frac{30}{24}\) = 1.25
= [\(\frac{1}{0.03 \times 0.024}\)]-1
= [\(\frac{0.024}{0.003}\)]-1
= \(\frac{0.03}{0.024}\)
= \(\frac{30}{24}\) = 1.25