JAMB - Mathematics (1997 - No. 39)
A number is selected at random between 10 and 20, both numbers inclusive. Find the probability that the number is an even number
\(\frac{5}{11}\)
\(\frac{1}{2}\)
\(\frac{6}{11}\)
\(\frac{7}{10}\)
Giải thích
n(even numbers between 10 and 20 inclusive) = 6
n(numbers between 10 and 20) = 11
P(even) = \(\frac{6}{11}\)