JAMB - Mathematics (1990 - No. 26)
At what value of x is the function x\(^2\) + x + 1 minimum?
-1
\(-\frac{1}{2}\)
\(\frac{1}{2}\)
1
Giải thích
x\(^2\) + x + 1
\(\frac{dy}{dx}\) = 2x + 1
At the turning point, \(\frac{dy}{dx}\) = 0
2x + 1 = 0
x = -\(\frac{1}{2}\)