JAMB - Mathematics (1988 - No. 35)
Simplify \(\frac{4a^2 - 49b^2}{2a^2 - 5ab - 7b^2}\)
\(\frac{a - b}{2a + b}\)
\(\frac{2a + 7b}{a - b}\)
\(\frac{2a - 7b}{a + b}\)
\(\frac{2a + 7b}{a + b}\)
Giải thích
\(\frac{4a^2 - 49b^2}{2a^2 - 5ab - 7b^2}\) = \(\frac{(2a)^2 - (7b)^2}{(a + b)(2a - 7b)}\)
= \(\frac{(2a + 7b)(2a - 7b)}{(a + b)(2a - 7b)}\)
= \(\frac{2a + 7b}{a + b}\)
= \(\frac{(2a + 7b)(2a - 7b)}{(a + b)(2a - 7b)}\)
= \(\frac{2a + 7b}{a + b}\)