JAMB - Mathematics (1983 - No. 33)
Simplify \(\sqrt[3]{\frac{27a^{-9}}{8}}\).
\(\frac{9a^2}{2a^3}\)
\(\frac{3}{2a^3}\)
\(\frac{2}{3a^2}\)
\(\frac{3a^2}{2}\)
Giải thích
\(\sqrt[3]{\frac{27a ^{-9}}{8}}\) = \(\frac{3a^{-3}}{2}\)
= \(\frac{3}{2}\) x \(\frac{1}{a^3}\)
= \(\frac{3}{2a^3}\)
= \(\frac{3}{2}\) x \(\frac{1}{a^3}\)
= \(\frac{3}{2a^3}\)