JAMB - Mathematics (1980 - No. 31)
Solve the equation for the positive values of \(\theta\) less than 360o. 3 tan \(\theta\) + 2 = -1
135o or 315o
45o or 135o
315o or 180o
315v + 45o
360o or 315o
Giải thích
3 tan \(\theta\) + 2 = -1
3 tan \(\theta\) \(\frac{-3}{3}\) = -1
\(\theta\) = tan -1(-1)
\(\theta\) = 360o - 45o
= 315o
\(\theta\) = 180 - 45o = 135o
3 tan \(\theta\) \(\frac{-3}{3}\) = -1
\(\theta\) = tan -1(-1)
\(\theta\) = 360o - 45o
= 315o
\(\theta\) = 180 - 45o = 135o