JAMB - Chemistry (2018 - No. 58)
The hydrogen ion concentration of a sample of orange juice is 2.0 X 10\(^{-11}\)moldm\(^{-3}\). What is its p\(^{OH}\)? [log102 = 0.3010]
3.30
13.00
10.70
11.30
Giải thích
PH+POH=14
p\(^{H}\) = Log [H\(^+\)]
p[H\(^+\) ] = 2.0 X 10\(^{-11}\)moldm\(^{-3}\)
p\(^{H}\) = Log [2.0 X 10\(^{-11}\)]
p\(^{H}\) = 10.70
10.70+ p\(^{OH}\) =14
p\(^{OH}\) = 14 -10.70
= 3.30