JAMB - Chemistry (2006 - No. 27)
The volume of 2.5 moles of oxygen at s.t.p is
[Molar volume of a gas at s.t.p = 22.4 dm3]
[Molar volume of a gas at s.t.p = 22.4 dm3]
50.0 dm3
84.0 dm3
28.0 dm3
56.0 dm3
Giải thích
1 mole of gas at s.t.p = 22.4
2.5 moles → 2.5 * 22.4 = 56.00 dm3
2.5 moles → 2.5 * 22.4 = 56.00 dm3