JAMB - Chemistry (1992 - No. 17)
A sample of orange juice is found to have a pH of 3.80. What is he concentration of the hydroxide ion in the juice?
1.6 x 10-4
6.3 x 10-11
6.3 x 10-4
1.6 x 10-11
Giải thích
pH + pOH = 14
3.80 + pOH = 14
pOH = 14 - 3.80
pOH = 10.2
Recall that pOH = - log [ OH\(^-\)]
10.2 = - log [ OH\(^-\)]
[ OH\(^-\)] = 10\(^{-10.2}\)
[ OH\(^-\)] = 6.3 x 10\(^{-11}\)