WAEC - Physics (2016 - No. 6)
An object of volume 400cm3 and 2.5gcm-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm-3)
1200g
1000g
800g
400g
Paliwanag
Mass = density x volume
400 x 2.5 = 1000g
Loss in mass = volume x density
= \(\frac{400}{2}\) x 1 = 200g
Reading on spring balance = 1000 - 200g = 800g
400 x 2.5 = 1000g
Loss in mass = volume x density
= \(\frac{400}{2}\) x 1 = 200g
Reading on spring balance = 1000 - 200g = 800g