WAEC - Physics (2002 - No. 20)
Water of mass 120g at 50oC is added to 200g of water at 10oC and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]
60oC
40oC
25oC
10oC
Paliwanag
120 x 4.2(50 - \(\theta\)) = 200 x 4.2(\(\theta\) - 10)
\(\theta = \frac{33600}{1344} = 25^oC\)
\(\theta = \frac{33600}{1344} = 25^oC\)