WAEC - Physics (1998 - No. 23)
A 90-W immersion heater is used to supply energy for five minutes. The energy supplied is used to completely melt 180g of a solid at is melting point. Neglecting energy losses to the surroundings, calculate the specific latent heat of fusion of the solid
0.5Jg-1
2.5Jg-1
15.0Jg-1
450.0Jg-1
150Jg-1
Paliwanag
Pt = mL
L = \(\frac{pt}{m} = \frac{90 \times 60 \times 5}{180}\)
= 150Jg\(^{-1}\)
L = \(\frac{pt}{m} = \frac{90 \times 60 \times 5}{180}\)
= 150Jg\(^{-1}\)