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WAEC - Further Mathematics (2024 - No. 20)

A particle starts from rest accelerates at 4ms\(^{-2}\). Find the distance covered after 4 seconds.
12 m
14 m
18 m
32 m

Paliwanag

s = ut + \(\frac{1}{2}\)at\(^2\)

u = 0 ms\(^{-1}\), t = 4 secs, a = 4ms\(^{-2}\)

S = 0.5 x 4 x 16 = 32 m

 

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