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WAEC - Chemistry (2002 - No. 3)
Consider the following equation; Cr
2
O
7(aq)
2-
+ 14H
+
(aq)
+ 6e
-
→ 2Cr
3+
(aq)
+ 7H
2
O
(I)
. The oxidation number of chromium changes from
-2 to + 3
- 2 to + 6
+ 6 to + 3
+ 7 to + 6
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