JEE Advance - Physics (1994 - No. 2)
A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration $${a_c}$$ is varying with time t as $${a_c}$$ = k2rt2 where k is a constant. The power delivered to the perticles by the force acting on it is:
$$2\pi m{k^2}{r^2}t$$
$$m{k^2}{r^2}t$$
$${{\left( {m{k^4}{r^2}{t^5}} \right)} \over 3}$$
zero