JEE Advance - Mathematics (2004 - No. 18)

If one of the diameters of the circle $${x^2} + {y^2} - 2x - 6y + 6 = 0$$ is a chord to the circle with centre (2, 1), then the radius of the circle is

$${\sqrt 3 }$$

$${\sqrt 2 }$$

JEE Advance - Mathematics (2004 - No. 18)

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