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JEE Advance - Mathematics (2003 - No. 16)

The centre of circle inscibed in square formed by the lines $${x^2} - 8x + 12 = 0\,\,and\,{y^2} - 14y + 45 = 0$$, is
(4, 7)
(7, 4)
(9, 4)
(4, 9)

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