JEE Advance - Mathematics (2000 - No. 6)

If $${x^2} + {y^2} = 1$$ then

$$yy'' - 2{\left( {y'} \right)^2} + 1 = 0$$

$$yy'' + {\left( {y'} \right)^2} + 1 = 0$$

$$yy'' + {\left( {y'} \right)^2} - 1 = 0$$

$$yy'' + 2{\left( {y'} \right)^2} + 1 = 0$$

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