JEE MAIN - Physics (2003 - No. 52)
Dimensions of $${1 \over {{\mu _0}{\varepsilon _0}}}$$, where symbols have their usual meaning, are
[ L-1T ]
[ L-2T2 ]
[ L2T-2 ]
[ LT-1 ]
Paliwanag
The velocity of light in vacuum is
c = $${1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$;
$$\therefore[{1 \over {{\mu _0}{\varepsilon _0}}}]$$ = [c2] = [L2T-2]
$$\therefore$$ Dimension of $${1 \over {{\mu _0}{\varepsilon _0}}}$$ = [L2T-2]
c = $${1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$;
$$\therefore[{1 \over {{\mu _0}{\varepsilon _0}}}]$$ = [c2] = [L2T-2]
$$\therefore$$ Dimension of $${1 \over {{\mu _0}{\varepsilon _0}}}$$ = [L2T-2]