JAMB - Physics (2012 - No. 28)
A glass block of thickness 10cm is placed on an object. If an observer views the object vertically, the displacement of the object is
3.33cm
5.00cm
6.67cm
8.50cm
Paliwanag
\(\mu\) = R.9 = 1.5 = 10
A.P A.d, Ad = 6.66
Displacement = R.d - A.d = 10 - 6.66
= 3.33
A.P A.d, Ad = 6.66
Displacement = R.d - A.d = 10 - 6.66
= 3.33