JAMB - Physics (2012 - No. 21)
The equation of a wave traveling in a horizontal direction is expressed as y = 15 sin \(\frac{2\pi}{5}\) (60t - x). What is its wavelength?
60m
15m
5m
2m
Paliwanag
Given: y = 15 sin \(\frac{2\pi}{5}\) (60t - x).
comparing y = 15 sin \(\frac{2\pi}{5}\) (60t - x) with the equation of wave motion Asin\(\frac{2\pi}{\lambda}\)(x - vt)
\(\frac{2\pi}{5}\) = \(\frac{2\pi}{\lambda}\)
Therefore, \(\lambda\) = 5m.