WAEC - Physics (2018 - No. 35)
A wire of length 400cm is stretched between two fixed points. When plucked, its fundamental frequency is 150Hz. Calculate the speed of the wave produced.
250\(ms^{-1}\)
625\(ms^{-1}\)
1200\(ms^{-1}\)
1500\(ms^{-1}\)
คำอธิบาย
The fundamental frequency \((f_{0})\) = \(\frac{v}{2l}\)
\(f_{0} = 150Hz; l =400cm = 4m\)
\(150 = \frac{v}{2\times 4}\)
\(v = 150 \times 8 = 1200ms^{-1}\)