WAEC - Mathematics (2021 - No. 4)

If log\(_{10}\) 2 = m and log\(_{10}\) 3 = n, find log\(_{10}\) 24 in terms of m and n.

3m + n

m + 3n

4mn

3mn

log\(_{10}\) 24 = log\(_{10}\) 8 \(\times\) log\(_{10}\) 3

where log\(_{10}\) 8 = 3 log\(_{10}\) 2 = 3 \(\times\) m

and log\(_{10}\) 3 = n

: log\(_{10}\) 24 = 3m + n