WAEC - Mathematics (2018 - No. 23)
Solved the equation \(2x^2 - x - 6\) = 0
x = \(\frac{-3}{2}\) or 2
x = -2 or \(\frac{3}{2}\)
x = -3 or 2
x = 3 or -2
คำอธิบาย
\(2x^2 - x - 6\) = 0
\(2x^2 - 4x + 3x - 6\) = 0
2x(x - 2) + 3(x - 2) = 0
(2x + 3) (x - 2) = 0
Either; 2x + 3 = 0 or x - 2 = 0
x = \(\frac{-3}{2}\) or x = 2