WAEC - Mathematics (2009 - No. 31)
Find the quadratic equation whose roots are -\(\frac{1}{2}\) and 3
2x2 - 2x + 3 = 0
2x2 - 2x - 3 = 0
2x2 - 5x - 3 = 0
3x2 - 5x - 3 = 0
คำอธิบาย
x = \(\frac{-1}{2}\)
x = 3
2x = -1, x = 3; 2x + 1 = 0
x - 3 = 0
(2x + 1)(x - 3) = 0
2x2 - 6x + x - 3 = 0
2x2 - 5x - 3 = 0
x = 3
2x = -1, x = 3; 2x + 1 = 0
x - 3 = 0
(2x + 1)(x - 3) = 0
2x2 - 6x + x - 3 = 0
2x2 - 5x - 3 = 0