WAEC - Mathematics (2008 - No. 6)
If p-2g + 1 = g + 3p and p - 2 = 0, find g
-2
-1
1
2
คำอธิบาย
p - 2g + 1 = g + 3p.........(1)
p - 2 = 0 .........(2)
From (2), p = 2; put p = 2 into (1);
2 - 2g + 1 = g + 3(2)
3 - 2g = g + 6
-2g - g = 6 - 3
-3g = 3
g = \(\frac{3}{-3}\)
g = -1
p - 2 = 0 .........(2)
From (2), p = 2; put p = 2 into (1);
2 - 2g + 1 = g + 3(2)
3 - 2g = g + 6
-2g - g = 6 - 3
-3g = 3
g = \(\frac{3}{-3}\)
g = -1