WAEC - Mathematics (2002 - No. 22)
Simplify \(\frac{1}{1-x} + \frac{2}{1+x}\)
\(\frac{x+3}{1-x^2}\)
\(\frac{x-3}{1+x^2}\)
\(\frac{3-x}{1-x^2}\)
\(\frac{3-x}{1+x^2}\)
คำอธิบาย
\(\frac{1}{1-x} + \frac{2}{1+x}\\
\frac{1+x+2-2x}{(1-x)(1+x)} = \(\frac{3-x}{1-x^2}\)\)
\frac{1+x+2-2x}{(1-x)(1+x)} = \(\frac{3-x}{1-x^2}\)\)