WAEC - Mathematics (2001 - No. 15)
Factorize \(6x^2 + 7x - 20\)
(6x - 5)(x + 4)
2(3x-5)(x+2)
(3x+4)(2x-5)
(3x-4)(2x+5)
คำอธิบาย
\(6x^2 + 7x - 20\)
= \(6x^2 + 15x - 8x - 20\)
= \(3x(2x + 5) - 4(2x + 5)\)
= \((3x - 4)(2x + 5)\)
\(6x^2 + 7x - 20\)
= \(6x^2 + 15x - 8x - 20\)
= \(3x(2x + 5) - 4(2x + 5)\)
= \((3x - 4)(2x + 5)\)