WAEC - Mathematics (2000 - No. 35)
Solve the equation \(3y^2\) = 27y
y = o or 3
y = 0 or 9
y = -3 or 3
y = 3 or 9
คำอธิบาย
3y\(^2\) = 27y
3y\(^2\) - 27y = 0
3y(y - 9) = 0
3y = 0 or y - 9 = 0
y = 0 or y = 9
y = 0 or 9
3y\(^2\) - 27y = 0
3y(y - 9) = 0
3y = 0 or y - 9 = 0
y = 0 or y = 9
y = 0 or 9