WAEC - Mathematics (1993 - No. 10)
Solve the equation x\(^2\) - 2x - 3 = 0
(-3, 1)
(-1, -3)
(3,1)
(43, 0)
(-1, 3).
คำอธิบาย
x\(^2\) - 2x - 3 = 0
x\(^2\) - 3x + x - 3 = 0
x(x - 3) + 1(x - 3) = 0
(x + 1)(x - 3) = 0
x = (-1, 3)
x\(^2\) - 2x - 3 = 0
x\(^2\) - 3x + x - 3 = 0
x(x - 3) + 1(x - 3) = 0
(x + 1)(x - 3) = 0
x = (-1, 3)