WAEC - Mathematics (1992 - No. 8)
Evaluate \(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
0.2
2
100
409
490
คำอธิบาย
\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
= \(\log_{10} (\frac{25 \times 32}{8})\)
= \(\log_{10} 100 \)
= 2
\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
= \(\log_{10} (\frac{25 \times 32}{8})\)
= \(\log_{10} 100 \)
= 2