WAEC - Mathematics (1991 - No. 7)
Factorize 3a\(^2\) - 11a + 6
(3a - 2)(a - 3)
(2a -2)(a - 3)
(3a - 2)(a + 3)
(3a + 2)(a - 3)
(2a-3)(a + 2)
คำอธิบาย
3a\(^2\) - 11a + 6
3a\(^2\) - 9a - 2a + 6
3a(a - 3) - 2(a - 3)
= (3a - 2)(a - 3)
3a\(^2\) - 11a + 6
3a\(^2\) - 9a - 2a + 6
3a(a - 3) - 2(a - 3)
= (3a - 2)(a - 3)