WAEC - Further Mathematics (2008 - No. 18)
Find the derivative of \(3x^{2} + \frac{1}{x^{2}}\)
\(6x + 2x^{2}\)
\(6x + \frac{1}{2x}\)
\(6x - \frac{2}{x^{3}}\)
\(6x - \frac{1}{2x}\)
คำอธิบาย
\(y = 3x^{2} + \frac{1}{x^{2}} \equiv y = 3x^{2} + x^{-2}\)
\(\frac{\mathrm d y}{\mathrm d x} = 6x - 2x^{-3}\)
= \(6x - \frac{2}{x^{3}}\)