WAEC - Chemistry (2015 - No. 21)
The number of oxygen molecules present in 16.0g of the gas is ______?
[Avogadro's number = 6.02 x 1023]
[Avogadro's number = 6.02 x 1023]
6.02 x 1022
6.02 x 1023
3.01 x 1023
1.51 x 1023
คำอธิบาย
1 mole = Molar mass of gas = Avogadros number
32g of O2 = 6.02 x 1023
16g of O2 = x
x = \(\frac{16 \times 6.02 \times 10^23}{32}\) = 3.01 x 1023
32g of O2 = 6.02 x 1023
16g of O2 = x
x = \(\frac{16 \times 6.02 \times 10^23}{32}\) = 3.01 x 1023