JEE Advance - Mathematics (2004 - No. 14)
Find the equation of circle touching the line 2x + 3y + 1 = 0 at (1, -1) and cutting orthogonally the circle having line segment joining (0, 3) and (- 2, -1) as diameter.
x^2 + y^2 - 5x - 2.5y + 0.5 = 0
2x^2 + 2y^2 + 10x + 5y + 1 = 0
x^2 + y^2 + 5x + 2.5y + 0.5 = 0
2x^2 + 2y^2 - 10x - 5y + 1 = 0
x^2 + y^2 - 10x - 5y + 1 = 0