JEE Advance - Mathematics (1997 - No. 24)
If $$g\left( x \right) = \int_0^x {{{\cos }^4}t\,dt,} $$ then $$g\left( {x + \pi } \right)$$ equals
$$g\left( x \right) + g\left( \pi \right)$$
$$g\left( x \right) - g\left( \pi \right)$$
$$g\left( x \right) g\left( \pi \right)$$
$${{g\left( x \right)} \over {g\left( \pi \right)}}$$